#include <iostream>
using namespace std;

/*
Shows how the comma operator can be used 
to create a single expression from two or more
expressions:  <exp1>,<exp2>.  
Both expressions are evaluated, but
the final expression <exp2> in the sequence determines
the value of the comma expression <exp1>,<exp2>.

Also shows the "short-circuit"
evaluation property of the ?: operator: the
decrement following the colon is not evaluated
when the predicate (the boolean test expression, here x==1) 
is true.
*/

int main(){
  int x = 1;
  cout << (x==1 ? ++x, ++x : --x ) << endl;
  return 0;
}