#include <iostream>
using namespace std;

/*  Illustrates the behavior of a/b and a%b with negative integer
    arguments a and b.  The behavior is system dependent: different
    platforms may give different answers, when one or more
    of the arguments a and b is negative.  The answers must 
    always satisfy the following equation:

	         a  ==  (a/b)*b + (a%b).
    
    When both a and b are positive, the values of a/b and a%b
    are uniquely determined, because 0 <= a%b < b is required.
    But when either a or b is negative, many systems allow a%b
    to be negative, even though the standard mathematical convention
    requires the remainder in integer division to be nonnegative
    in all cases.
*/

int main(){
  cout << " -4 / 7 = " << ( -4 / 7 ) << endl;
  cout << " -4 % 7 = " << ( -4 % 7 ) << endl << endl;

  cout << " (-4) / 7 = " << ( (-4) / 7 ) << endl;          // Redundant.
  cout << " (-4) % 7 = " << ( (-4) % 7 ) << endl << endl;

  cout << " 4 / -7 = " << ( 4 / -7 ) << endl;
  cout << " 4 % -7 = " << ( 4 % -7 ) << endl << endl;

  cout << " -4 / -7 = " << ( -4 / -7 ) << endl;
  cout << " -4 % -7 = " << ( -4 % -7 ) << endl << endl;
  return 0;
}
/*   Output on kiwi.cs.ucla.edu:

  -4 / 7 = 0
  -4 % 7 = -4

 (-4) / 7 = 0
 (-4) % 7 = -4

  4 / -7 = 0
  4 % -7 = 4

 -4 / -7 = 0
 -4 % -7 = -4

*/