On December 11 2002 I posted a message to the number theory list that contained the following:
A paper by Andrew Bremner and Richard Guy published January 1988, "A Dozen Difficult Diophantine Dilemmas" has:

A) E.T. Prothro xy(x^4 - y^4) = 2zw(z^4-w^4) (1) and,
B) Ernest J. Eckert xy(x^4 - y^4) = zw(z^4-w^4) (2)

C) "Computer searches over a small range failed to find any solution to (1) or (2)."

In the usual notation for exponentiation these equations are:
xy(x4 - y4) = 2zw(z4-w4) (1) and,
xy(x4 - y4) = zw(z4-w4) (2)
and as will shortly be obvious (1) expresses the following question. Are there two distinct Pythagorean triples, side-lengths of right triangles, so that a product of the three (lengths of each triangle's sides) is the same?
Two individuals responded. Their correspondence led me to seek the definition of primitive right triangles and Pythagorean triples; Google search led to these online references, and the hardcopy version, Eric W. Weisstein, World of Mathematics, 1999, CRC Press LLC. A series of reading steps led to the following statment in a paper by Olga Taussky, "The Many Aspects of the Pythagorean Triangles," Linear Algebra and its Applications 43:285-295, 1982:

"All of the Pythagorean triples are known to us. They are given by the expressions

l(m2 - n2), l2mn, l(m2 + n2).

Here l, m, n are whole numbers."

Verification of matrix transformation of (3, 4, 5) into other Pythagorean triples Mathematica computations: (5, 12, 13); (21, 20, 29); and (15, 8, 17).
"For any Pythagorean triple, the product of the two nonhypotenuse legs (i.e., the two smaller numbers) is always divisible by 12, and the product of all three sides is divisible by 60.

It is not known if there are two distinct triples having the same product. The existence of two such triples corresponds to a nonzero solution to the Diophantine equation

xy(x4 - y4) = zw(z4-w4)

(Guy 1994, p. 188." Pythagorean Triples).

From Right Triangle:

For a right triangle with integer side lengths, note that any Pythagorean triple can be written
a = m2 - n2(9)
b = 2mn (10)
c = m2 + n2(11)
The triangle area is ab/2 and the radius of an inscribed circle,

r = ab/(a+b+c)

Euclid's first lemma [proposition 29] and a recent book

More things I've run across about these issues (including references) are at Pythagorean triples.
9/14/04 Version http://www.cs.ucla.edu/~klinger/nmath/pyth_triples.html
©2004 Allen Klinger